१. भाग १ सोडवू (पहिला कंस):
$$(4 + 2 - 4 + 3) = 6 - 4 + 3 = 5$$
२. भाग २ सोडवू (महिरपी कंस):
$$\left\{\frac{1 + 8 \times 7}{19}\right\} = \left\{\frac{1 + 56}{19}\right\} = \frac{57}{19} = 3$$
३. भाग ३ सोडवू (मोठा कंस):
$$[(3 + 5 - 4) + (17 - 9 \times 4)]$$
$$= [(8 - 4) + (17 - 36)] = [4 + (-19)] = 4 - 19 = -15$$
४. कंचेभागुबेव नियमानुसार गुणाकार आधी करून बेरीज करू:
$$= 5 + 3 \times (-15)$$
$$= 5 - 45 = \mathbf{-40}$$
1. Solve Part 1 (First bracket):
$$(4 + 2 - 4 + 3) = 6 - 4 + 3 = 5$$
2. Solve Part 2 (Curly braces with fraction):
$$\left\{\frac{1 + 8 \times 7}{19}\right\} = \left\{\frac{1 + 56}{19}\right\} = \frac{57}{19} = 3$$
3. Solve Part 3 (Square brackets):
$$[(3 + 5 - 4) + (17 - 9 \times 4)]$$
$$= [(8 - 4) + (17 - 36)] = [4 + (-19)] = 4 - 19 = -15$$
4. Combine all parts using BODMAS (multiplication before addition):
$$= 5 + 3 \times (-15)$$
$$= 5 - 45 = \mathbf{-40}$$
आधी $(5 + 3 = 8)$ करू नये! गुणाकार $3 \times (-15) = -45$ आधी होतो, मग $5 - 45 = -40$ मिळते.
Remember that $3 \times (-15)$ must be performed before adding 5: $5 + (-45) = -40$, not $(5 + 3) \times (-15)$.
कंचेभागुबेव: गुणाकार बेरजेच्या आधी! $5 + [3 \times (-15)] = 5 - 45 = \mathbf{-40}$!
BODMAS: Multiplication precedes addition! $5 + 3 \times (-15) = 5 - 45 = \mathbf{-40}$!
१. 335: चिन्हांची मोठी चूक.
२. -225: चुकीची गणना.
३. -40: अचूक उत्तर ($5 - 45 = -40$).
४. 40: धन चिन्हाची चूक.
1. 335: Incorrect sign handling in brackets.
2. -225: Multiplying $(5 + 3) \times (-15) = 8 \times (-15) = -120$ or similar violation.
3. -40: Exact verified BODMAS result: $5 - 45 = -40$!
4. 40: Sign error (positive instead of negative).