१. BODMAS नियमानुसार:
$$2 + \left(\frac{4}{A+6}\right) \times 2 = \frac{16}{7}$$
$$2 + \frac{8}{A+6} = \frac{16}{7}$$
२. दोन्ही बाजूंमधून 2 वजा करू:
$$\frac{8}{A+6} = \frac{16}{7} - 2 = \frac{16 - 14}{7} = \frac{2}{7}$$
३. तिरकस गुणाकार करून सोडवू:
$$2(A + 6) = 8 \times 7 = 56$$
$$A + 6 = 28 \implies A = 28 - 6 = \mathbf{22}$$
1. Apply BODMAS order of operations:
$$2 + \left(\frac{4}{A+6}\right) \times 2 = \frac{16}{7}$$
$$2 + \frac{8}{A+6} = \frac{16}{7}$$
2. Subtract 2 from both sides:
$$\frac{8}{A+6} = \frac{16}{7} - 2 = \frac{16 - 14}{7} = \frac{2}{7}$$
3. Cross-multiply and solve for $A$:
$$2(A + 6) = 8 \times 7 = 56$$
$$A + 6 = 28 \implies A = 28 - 6 = \mathbf{22}$$
आधी $(2 + 4)$ जोडू नये! BODMAS नियमानुसार भागाकार व गुणाकार आधी होतात.
Do not add $(2 + 4 = 6)$ first! Division and multiplication take precedence over addition.
कंचेभागुबेव: कंस $\to$ भागाकार $\to$ गुणाकार $\to$ बेरीज!
BODMAS: Brackets $\to$ Division $\to$ Multiplication $\to$ Addition!
१. 22: $2 + \frac{8}{28} = 2 + \frac{2}{7} = \frac{16}{7}$, अचूक जुळते!
२. 21: $2 + \frac{8}{27} \neq \frac{16}{7}$.
३. 20: $2 + \frac{8}{26} \neq \frac{16}{7}$.
४. 23: $2 + \frac{8}{29} \neq \frac{16}{7}$.
1. 22: $2 + \frac{8}{28} = 2 + \frac{2}{7} = \frac{16}{7}$, perfectly verified!
2. 21: $2 + \frac{8}{27} \neq \frac{16}{7}$.
3. 20: $2 + \frac{8}{26} \neq \frac{16}{7}$.
4. 23: $2 + \frac{8}{29} \neq \frac{16}{7}$.