सविस्तर स्पष्टीकरण (Detailed Explanation):
अचूक उत्तर: पर्याय (2)
Shortcut Trick
गणना:
टाकीची क्षमता 96 एकक मानू [12, 24, 32 चा लसावि]
A पाईपची क्षमता = 96 ÷ 12 = 8 एकक/मिनिट
B पाईपची क्षमता = 96 ÷ 24 = 4 एकक/मिनिट
C पाईपची क्षमता = 96 ÷ 32 = -3 एकक/मिनिट
A + B + C ची एकत्रित क्षमता = 9 एकक/मिनिट
जर C हा 2 मिनिटांपूर्वी बंद केला नसता तर
C ने 2 मिनिटांत केलेले कार्य = 2 x -3 = -6 एकक मानू
म्हणून, सर्व पाईपने केलेले एकूण कार्य = 96 + (-6) = 90 एकक
म्हणून, अपेक्षित वेळ = एकूण काम/एकूण कार्यक्षमता
म्हणून, अपेक्षित वेळ = 90 ÷ 9 = 10 मिनिटे
∴ अपेक्षित वेळ 10 मिनिटे आहे.
Alternate
वापरलेली संकल्पना:
एकूण कार्य = कार्यक्षमता x वेळ
गणना:
टाकीची क्षमता 96 एकक मानू [12, 24, 32 चा लसावि]
A पाईपची क्षमता = 96 ÷ 12 = 8 एकक/मिनिट
B पाईपची क्षमता = 96 ÷ 24 = 4 एकक/मिनिट
C पाईपची क्षमता = 96 ÷ 32 = -3 एकक/मिनिट
A + B + C ची एकत्रित क्षमता = 9 एकक/मिनिट
A + B ची एकत्रित क्षमता = 12 एकक/मिनिट
B = 12 एकक/मिनिट
प्रश्नानुसार
टाकी भरण्याच्या 2 मिनिटे आधी पाईप C बंद केला जातो.
म्हणून, शेवटच्या 2 मिनिटांत A + B ने केलेले कार्य = 12 x 2 = 24 एकक
टाकीची उर्वरित क्षमता = 96 - 24 = 72 एकक
आता टाकीची उर्वरित क्षमता सर्व पाईपने भरली आहे
म्हणून, वेळ = 72 ÷ 9 = 8 मिनिटे
∴ टाकी भरण्यासाठी लागणारा एकूण वेळ = 2 मिनिटे + 8 मिनिटे = 10 मिनिटे.
Shortcut Trick
Total Capacity (LCM of 12, 24, 32) = 96 units.
Efficiencies: A = 8, B = 4, C = −3 (emptying).
Net efficiency (A + B − C) = 8 + 4 − 3 = 9 units/min.
Work not emptied by C in the last 2 minutes = 3 × 2 = 6 units.
Time taken to fill = (96 − 6) ÷ 9 = 90 ÷ 9 = 10 minutes.
∴ The correct answer is 10 minutes.
Alternate Method
Given:
Time taken by Pipe A = 12 minutes
Time taken by Pipe B = 24 minutes
Time taken by Pipe C (emptying) = 32 minutes
Formula Used:
Total Work = Efficiency × Time
+--------+------+------------+------------+
| Person | Days | Total Work | Efficiency |
+--------+------+------------+------------+
| Pipe A | 12 | 96 | 8 |
| Pipe B | 24 | 4 | |
| Pipe C | 32 | −3 | |
+--------+------+------------+------------+
Calculations:
Let the total time to fill the tank be T minutes.
Pipe A and B work for the entire duration T.
Pipe C is closed 2 minutes before filling, so Pipe C works for (T − 2) minutes.
⇒ Work done by A + Work done by B − Work emptied by C = Total capacity
⇒ (8 × T) + (4 × T) − 3 × (T − 2) = 96
⇒ 12T − 3T + 6 = 96
⇒ 9T + 6 = 96
⇒ 9T = 90
⇒ T = 10 minutes
∴ The correct answer is 10 minutes.
Related Concepts:
Pipes and Cisterns Logic
Filling pipes have positive efficiency, while emptying pipes (leaks) have negative efficiency. Net efficiency is the algebraic sum of all active pipe efficiencies.
Closing Pipes Early
If a pipe is closed x minutes before completion, assume it works for (T − x) minutes, where T is the total time.
Efficiency Relationship
Efficiency is inversely proportional to the time taken to complete the task alone, given constant total work (Efficiency = Total Work ÷ Time).
∴ The correct answer is 10 minutes.